Gambarsaeoux

7a Graphing Quadratic Functions Practice The axis of symmetry is the xcoordinate vertex of the parabola The general form to find the axis of symmetry is For y =x^2 4x 2, a=1, b=−4 and c=2 If the function is symmetrical about the line x=0, it is an even function, so cannot have any odddegree terms The only viable choice is1) y = x^2 4x 2 First find the axis of symmetry (x= b/(2a)) find the vertex from that and it helps you choose the values for x when you make your x/y tables In this equation a = 1; Y=x^2-4x+1 axis of symmetry

The equation is not exact, because you'd actually need d (2xy)/dy=d (x 2 y 2 )/dx, which means that 2x=2x Letting (x 2 y 2 )=M, 2xy=N, then Mx=2x, Ny=2x So MxNy=4x Now, (MxNy)/N=4x/ (2xy)=2/y, so this is just a function of y v (y) That means that we can let u (y)=e integral of vdy u (y)=e 2ln y =1/y 2